ALL vs. AML Case Study To identify genes that can differentiate ALL vs. AML, and predict the type of unknown samples using the expression values of these genes.

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This set of 35 genes have distinct expression patterns between ALL and AML in the training data set. ALL = sample 1 – 27 AML = sample 28 – 38
The same set of 35 genes correctly predict the sample type in the independent data set. AML = The left half of the tree (sample 66,50,51,53,62,64,57,60,65,52,63,54,58,61 )
Examine the functions of the 35 genes with Gene Ontology Annotation Tool, which are: Cell cycle control DNA replication initiation Cytoskeletal anchoring RNA processing Nucleoside metabolism Protein metabolism and modification